![]() This qualitatively seems right because the probability of her winning any given race is 0.79527073. Sanity check: if Victory wins all four races with probability 0.4 then it is very likely she will win at least one of her next four races. The probability of Victory winning at least one race = 1 - ( probability of Victory losing all of the next 4 races) = 0.99824321Īnswer: Victory wins at least one of her next four races with probability This means she loses a given race with probability 1-0.79527073 = 0.20472927 It is given that she wins the next four races with probability 0.4: Let x = probability of Victory winning any one race of the next four races I think the proper approach is as follows: P(winning at least once out of the next four races) = 1 - P(losing all four of the races) ![]() One can compute the probability Victory loses all of her next four races and then subtract that result from 1 to get the above answer. So the probabilities that must be found and added are: Means they want the probability of Victory winning 1, 2, 3, or 4 out of her next 4 races. "What is the probability of Victory the Horse winning at least one race? " The next part I can say with relative certainty: (If there is any additional information to indicate this is not the case, please repost the question in its corrected form, for the rest of my answer depends on the above interpretation) Victory the horse has a 40% chance of winning ALL of her next 4 races. "At a horse track, Victory the Horse, has a 40% chance of winning the next 4 races." You can put this solution on YOUR website! Thank you!!Īnswer by math_helper(2414) ( Show Source): I’d just feel a lot better if I had some advice. And the following questions are even worse. Is that the answer to the question? Or do I divide that by 25 to result in 1.52/4 chance of winning the 4 races?įurthermore, if the question is asking about the probability of her winning ALL of them, would I calculate 38/100 *38/100 * 38/100 * 38/100? I repeated 25 times until the “horse” ran 100 “races”. The third simulation she won 2/4, and so forth. So, the first simulation of the 4 races, she won 2/4. So the simulation I did was drawing the numbers 1-10 (numbers 1-4 represent win, 5-10 represent loss) and summoned 4 numbers (one for each race). Is it asking the probability of the horse winning ALL 4 races? Or once? And I think I am doing something wrong because I am getting the same calculation for both. The issue I am having, is trying to figure out what this question is asking me. What is the probability of Victory the Horse winning at least one race? This assignment is on Simulation, and the Probability Statistics app on the calculator.Ĭreate a simulation to represent the following situations:Īt a horse track, Victory the Horse, has a 40% chance of winning the next 4 races. We have been using graphing calculators to explore theoretical and experimental probabilities, and I understand the difference between the two. This is more advanced than my current lessons. I have noticed on some online forums that other ways to solve probabilities are by using formulas that may look like this for example: p(E)=n(E)/n(S). I am studying Grade 12 Math online, and I am stuck on a few probability questions, (I’ll just post the first one for now to see if I catch on) and I think it’s because of how they are worded. ![]() Question 1113107: Hello! Thank you to anyone who may be taking time out of their day to read this. Click here to see ALL problems on Probability-and-statistics.
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